(18n^2-9n+1)/(3n-1)

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Solution for (18n^2-9n+1)/(3n-1) equation: 


D( n )

3*n-1 = 0

3*n-1 = 0

3*n-1 = 0

3*n-1 = 0 // + 1

3*n = 1 // : 3

n = 1/3

n in (-oo:1/3) U (1/3:+oo)

(18*n^2-(9*n)+1)/(3*n-1) = 0

(18*n^2-9*n+1)/(3*n-1) = 0

18*n^2-9*n+1 = 0

18*n^2-9*n+1 = 0

DELTA = (-9)^2-(1*4*18)

DELTA = 9

DELTA > 0

n = (9^(1/2)+9)/(2*18) or n = (9-9^(1/2))/(2*18)

n = 1/3 or n = 1/6

(n-1/6)*(n-1/3) = 0

((n-1/6)*(n-1/3))/(3*n-1) = 0

( n-1/3 )

n-1/3 = 0 // + 1/3

n = 1/3

( n-1/6 )

n-1/6 = 0 // + 1/6

n = 1/6

n in { 1/3} 

n = 1/6

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